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Baseball riddle time.

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  • 99explorer
    replied
    I remembered that rule because I was once thrown out trying to stretch a double into a triple.

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  • MattM37
    replied
    I'd forgotten about a hitter being credited with the base even if he's thrown out trying to take the next one. I think if I'd remembered that to begin with, I would have come pretty close to getting the whole thing.

    I did see a hit batter just once, and I remember it was a Mets game in the 80s, but that's all I recall.

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  • 99explorer
    replied
    Okay, here's the deal. First two batters hit triples and are thrown out at home trying to score. Two outs.
    Third batter hits a double. Fourth batter also hits a double, but the lead runner holds up at third for some reason, maybe with a limp.
    Fifth batter hits an infield single, and the runners hold. Bases loaded.
    Sixth batter hits a line drive that touches one of the base-runners, making the third out, but by rule, is credited with a single.
    Matt was right about the hit base-runner. So rare, I've never seen it happen.
    Thanks for playing.

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  • bowhunter75richard
    replied
    I agree with Matt. With the number of runners and the allotted value of hits, unless there is a technical aspect outside of the info given, I can not see this as possible. The first two outs would need to be the triples, otherwise a runner would have scored ahead of them. With only one more out available, and following hit would score a run. But then I assume you would not ask the question if the scenario was not possible !

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  • MattM37
    replied
    Given the ridiculous inclusion of instant replay challenges nowadays, imagine how *&%$-ing long that half-inning would be!

    Anyway, I'm thinking there would have to be some play(s) involving a runner crossing the plate but the run not counting. Given that number of baserunners and only the standard three outs.

    I'm also thinking there might be a hit base-runner in there somewhere. There would have to be plays where a lot of things happen. In a batter-by-batter scenario, you get to three outs all too soon.
    Last edited by MattM37; 08-07-2019, 04:21 PM.

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  • 99explorer
    replied
    Matt - No, but if you can think of more than one, be my guest.

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  • MattM37
    replied
    Are you sure there's only one possible way?

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  • 99explorer
    replied
    BHR - You are off to a good start with the two triples and two out. Now all you need is two doubles and two singles, and you have only one more out.

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  • bowhunter75richard
    replied
    I would imagine that the resulting complexities would be too involved to fit into the allotted space here to answer. There would need to be a man thrown out at the plate, but given he had rounded third in the first place, he would be given a triple. If this could happen twice in the same inning at some point in the inning.........? Also there would need to be a double play figured into the equation somewhere. But I really need to organize my sock drawer and do not have the time now to go further, sorry !

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  • 99explorer
    started a topic Baseball riddle time.

    Baseball riddle time.

    How can a team hit two triples, two doubles and two singles in an inning and fail to score a run?

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